second operand造句
例句與造句
- the type of the second operand must be an
第二個(gè)操作數(shù)的類(lèi)型必須是 - shifts its first operand right by the number of bits specified by its second operand
將第一個(gè)操作數(shù)向右移動(dòng)第二個(gè)操作數(shù)指定的位數(shù)。 - shifts its first operand left by the number of bits specified by its second operand
)將第一個(gè)操作數(shù)向左移動(dòng)第二個(gè)操作數(shù)指定的位數(shù)。 - and the third uses dictionary access to the class . note that the second operand of the
的默認(rèn)屬性這一情況，第三行使用對(duì)類(lèi)的字典訪問(wèn)。 - 64-bit quantity, the shift count is given by the low-order six bits of second operand
（64位數(shù)），則移位數(shù)由第二個(gè)操作數(shù)的低6位給出。 - It's difficult to find second operand in a sentence. 用second operand造句挺難的
- 32-bit quantity, the shift count is given by the low-order five bits of second operand
（32位數(shù)），則移位數(shù)由第二個(gè)操作數(shù)的低5位給出。 - the type of the first operand must be the user-defined type, and the type of the second operand must be
）；第一個(gè)操作數(shù)的類(lèi)型必須為用戶定義的類(lèi)型，第二個(gè)操作數(shù)的類(lèi)型必須為 - pops 1 value off the stack for the first operand, and 1 value of the stack for the second operand
對(duì)于第一個(gè)操作數(shù)，從堆棧中彈出1個(gè)值；對(duì)于第二個(gè)操作數(shù)，從堆棧中彈出1個(gè)值。 - pushes 1 value onto the stack for the first operand, and 1 value onto the stack for the second operand
對(duì)于第一個(gè)操作數(shù)，將1個(gè)值推到堆棧上；對(duì)于第二個(gè)操作數(shù)，將1個(gè)值推到堆棧上。 - expression requires the first operand to be of a reference type and the second operand to be the name of a data type
表達(dá)式要求第一個(gè)操作數(shù)為引用類(lèi)型，第二個(gè)操作數(shù)為數(shù)據(jù)類(lèi)型的名稱。 - 64-bit quantity, the shift count is given by the low-order six bits of the second operand second operand 0x3f
（64位數(shù)），則移位數(shù)由第二個(gè)操作數(shù)的低六位給出（第二個(gè)操作數(shù)&0x3f）。 - 64-bit quantity, the shift count is given by the low-order six bits of the second operand second operand 0x3f
（64位數(shù)），則移位數(shù)由第二個(gè)操作數(shù)的低六位給出（第二個(gè)操作數(shù)&0x3f）。 - pops a reference off the stack for the first operand, and a value off the stack for the second operand
對(duì)于第一個(gè)操作數(shù)，從堆棧中彈出一個(gè)引用；對(duì)于第二個(gè)操作數(shù)，從堆棧中彈出一個(gè)值。 - 32-bit quantity, the shift count is given by the low-order five bits of the second operand second operand 0x1f
（32位數(shù)），則移位數(shù)由第二個(gè)操作數(shù)的低五位給出（第二個(gè)操作數(shù)&0x1f）。 - 32-bit quantity, the shift count is given by the low-order five bits of the second operand second operand 0x1f
（32位數(shù)），則移位數(shù)由第二個(gè)操作數(shù)的低五位給出（第二個(gè)操作數(shù)&0x1f）。
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